Vs = 10 & 15v
R = 1k ohms
10 Volts 15 Volts
Volt drop v1 5.04v 5.16v
Volt drop v2 .74v .76v
volt drop v3 5.78v 5.93v
Volt drop v4 4.19v 9.02v
Caculated current A 4.19mA 9.02mA
With the Zener diode in reverse polarity it drops it rated voltage which is why V1 is around 5v. Because the other diode is in foward polarity it only uses up its rated .7v.
You need to explain in more detail why this is happening also adding extra pages will make it easier to follow
ReplyDeleteHi Aero you need to update your blog adjusting it depending on my comments, also try not to get to far behind writing up your experiments
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